3D collision detection - Game development | MDN (2022)

As with 2D collision detection, axis-aligned bounding boxes (AABB) are the quickest algorithm to determine whether the two game entities are overlapping or not. This consists of wrapping game entities in a non-rotated (thus axis-aligned) box and checking the positions of these boxes in the 3D coordinate space to see if they are overlapping.

The axis-aligned constraint is there because of performance reasons. The overlapping area between two non-rotated boxes can be checked with logical comparisons alone, whereas rotated boxes require additional trigonometric operations, which are slower to calculate. If you have entities that will be rotating, you can either modify the dimensions of the bounding box so it still wraps the object, or opt to use another bounding geometry type, such as spheres (which are invariant to rotation.) The animated GIF below shows a graphic example of an AABB that adapts its size to fit the rotating entity. The box constantly changes dimensions to snugly fit the entity contained inside.

Checking if a point is inside an AABB is pretty simple — we just need to check whether the point's coordinates fall inside the AABB; considering each axis separately. If we assume that P_x, P_y and P_z are the point's coordinates, and B_minX–B_maxX, B_minY–B_maxY, and B_minZ–B_maxZ are the ranges of each axis of the AABB, we can calculate whether a collision has occurred between the two using the following formula:

$f(P,B)= (P$x >= B{minX} \wedge Px <= B{maxX}) \wedge (Py >= B{minY} \wedge Py <= B{maxY}) \wedge (Pz >= B{minZ} \wedge Pz <= B{maxZ})

Or in JavaScript:

function isPointInsideAABB(point, box) { return (point.x >= box.minX && point.x <= box.maxX) && (point.y >= box.minY && point.y <= box.maxY) && (point.z >= box.minZ && point.z <= box.maxZ);}

Checking whether an AABB intersects another AABB is similar to the point test. We just need to do one test per axis, using the boxes' boundaries. The diagram below shows the test we'd perform over the X-axis — basically, do the ranges A_minX–A_maxX and B_minX–B_maxX overlap?

Mathematically this would look like so:

$f(A,B) =$

And in JavaScript, we'd use this:

function intersect(a, b) { return (a.minX <= b.maxX && a.maxX >= b.minX) && (a.minY <= b.maxY && a.maxY >= b.minY) && (a.minZ <= b.maxZ && a.maxZ >= b.minZ);}

To check whether a sphere contains a point we need to calculate the distance between the point and the sphere's center. If this distance is smaller than or equal to the radius of the sphere, the point is inside the sphere.

Taking into account that the Euclidean distance between two points A and B is $\sqrt{(A_x - B_x) ^ 2) + (A_y - B_y)^2 + (A_z - B_z)}$ , our formula for point vs. sphere collision detection would work out like so:

$f(P,S) = S_{radius} >= \sqrt{(P_x - S_x)^2 + (P_y - S_y)^2 + (P_z - S_z)^2}$

Or in JavaScript:

function isPointInsideSphere(point, sphere) { var distance = Math.sqrt((point.x - sphere.x) * (point.x - sphere.x) + (point.y - sphere.y) * (point.y - sphere.y) + (point.z - sphere.z) * (point.z - sphere.z)); return distance < sphere.radius;}

Note: The code above features a square root, which can be expensive to calculate. An easy optimization to avoid it consists of comparing the squared distance with the squared radius, so the optimized equation would instead involve distanceSqr < sphere.radius * sphere.radius.

The sphere vs sphere test is similar to the point vs sphere test. What we need to test here is that the distance between the sphere's centers is less than or equal to the sum of their radii.

Mathematically, this looks like:

$f(A,B) = \sqrt{(A$x - B_x)^2 + (A_y - B_y)^2 + (A_z - B_z)^2} <= A{radius} + B_{radius}

Or in JavaScript:

function intersect(sphere, other) { var distance = Math.sqrt((sphere.x - other.x) * (sphere.x - other.x) + (sphere.y - other.y) * (sphere.y - other.y) + (sphere.z - other.z) * (sphere.z - other.z)); return distance < (sphere.radius + other.radius);}

Testing whether a sphere and an AABB are colliding is slightly more complicated, but still simple and fast. A logical approach would be to check every vertex of the AABB, doing a point vs sphere test for each one. This is overkill, however — testing all the vertices is unnecessary, as we can get away with just calculating the distance between the AABB's closest point (not necessarily a vertex) and the sphere's center, seeing if it is less than or equal to the sphere's radius. We can get this value by clamping the sphere's center to the AABB's limits.

In JavaScript, we'd do this test like so:

function intersect(sphere, box) { var x = Math.max(box.minX, Math.min(sphere.x, box.maxX)); var y = Math.max(box.minY, Math.min(sphere.y, box.maxY)); var z = Math.max(box.minZ, Math.min(sphere.z, box.maxZ)); var distance = Math.sqrt((x - sphere.x) * (x - sphere.x) + (y - sphere.y) * (y - sphere.y) + (z - sphere.z) * (z - sphere.z)); return distance < sphere.radius;}

3D physics engines provide collision detection algorithms, most of them based on bounding volumes as well. The way a physics engine works is by creating a physical body, usually attached to a visual representation of it. This body has properties such as velocity, position, rotation, torque, etc., and also a physical shape. This shape is the one that is considered in the collision detection calculations.

We have prepared a live collision detection demo (with source code) that you can take a look at to see such techniques in action — this uses the open-source 3D physics engine cannon.js.

Related articles on MDN:

• Bounding volumes collision detection with Three.js
• 2D collision detection

External resources:

• Simple intersection tests for games on Gamasutra
• Bounding volume on Wikipedia